Cindy, Dana and Mary were playing with beads. Cindy started with 80 beads and in the first game, she won ³₄ more beads from Dana. In the second game, Cindy lost ⁵₈ of her original number of beads to Mary. Dana lost as many beads as Cindy to Mary. In the final game, Cindy won ¹₅ of her original number of beads from Dana. All of them ended up with the same number of beads.

1. How many beads did Cindy have in the end?
2. How many beads did Dana have at first?

	Cindy	Dana	Mary
Before	80
First game	+ 60	- 60
Second game	- 50		+ 50
		- 50	+ 50
Final game	+ 16	- 16
After	1 u	1 u	1 u

(a)
Number of beads that Cindy won from Dana
= ³₄ x 80
= 60

Number of beads that Cindy lost to Mary
= ⁵₈ x 80
= 50

Number of beads that Cindy won from Dana
= ¹₅ x 80
= 16

Number of beads that Cindy had in the end
= 80 + 60 - 50 + 16
= 106

(b)
Number of beads that Dana had at first
= 1 u + 16 + 50 + 60
= 106 + 16 + 50 + 60
= 232 

Answer(s): (a) 106 ; (b) 232