Tammy, Jaslyn and Nicole were playing with beads. Tammy started with 96 beads and in the first game, she won
14 more beads from Jaslyn. In the second game, Tammy lost
38 of her original number of beads to Nicole. Jaslyn lost as many beads as Tammy to Nicole. In the final game, Tammy won
12 of her original number of beads from Jaslyn. All of them ended up with the same number of beads.
- How many beads did Tammy have in the end?
- How many beads did Jaslyn have at first?
|
Tammy |
Jaslyn |
Nicole |
Before |
96 |
|
|
First game |
+ 24 |
- 24 |
|
Second game |
- 36 |
|
+ 36 |
|
|
- 36 |
+ 36 |
Final game |
+ 48 |
- 48 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Tammy won from Jaslyn
=
14 x 96
= 24
Number of beads that Tammy lost to Nicole
=
38 x 96
= 36
Number of beads that Tammy won from Jaslyn
=
12 x 96
= 48
Number of beads that Tammy had in the end
= 96 + 24 - 36 + 48
= 132
(b)
Number of beads that Jaslyn had at first
= 1 u + 48 + 36 + 24
= 132 + 48 + 36 + 24
= 240
Answer(s): (a) 132 ; (b) 240