Jean, Barbara and Lynn were playing with beads. Jean started with 35 beads and in the first game, she won ³₅ more beads from Barbara. In the second game, Jean lost ⁵₇ of her original number of beads to Lynn. Barbara lost as many beads as Jean to Lynn. In the final game, Jean won ¹₅ of her original number of beads from Barbara. All of them ended up with the same number of beads.

1. How many beads did Jean have in the end?
2. How many beads did Barbara have at first?

	Jean	Barbara	Lynn
Before	35
First game	+ 21	- 21
Second game	- 25		+ 25
		- 25	+ 25
Final game	+ 7	- 7
After	1 u	1 u	1 u

(a)
Number of beads that Jean won from Barbara
= ³₅ x 35
= 21

Number of beads that Jean lost to Lynn
= ⁵₇ x 35
= 25

Number of beads that Jean won from Barbara
= ¹₅ x 35
= 7

Number of beads that Jean had in the end
= 35 + 21 - 25 + 7
= 38

(b)
Number of beads that Barbara had at first
= 1 u + 7 + 25 + 21
= 38 + 7 + 25 + 21
= 91 

Answer(s): (a) 38 ; (b) 91