Wendy, Xylia and Betty were playing with beads. Wendy started with 80 beads and in the first game, she won ¹₂ more beads from Xylia. In the second game, Wendy lost ⁵₈ of her original number of beads to Betty. Xylia lost as many beads as Wendy to Betty. In the final game, Wendy won ¹₅ of her original number of beads from Xylia. All of them ended up with the same number of beads.

1. How many beads did Wendy have in the end?
2. How many beads did Xylia have at first?

	Wendy	Xylia	Betty
Before	80
First game	+ 40	- 40
Second game	- 50		+ 50
		- 50	+ 50
Final game	+ 16	- 16
After	1 u	1 u	1 u

(a)
Number of beads that Wendy won from Xylia
= ¹₂ x 80
= 40

Number of beads that Wendy lost to Betty
= ⁵₈ x 80
= 50

Number of beads that Wendy won from Xylia
= ¹₅ x 80
= 16

Number of beads that Wendy had in the end
= 80 + 40 - 50 + 16
= 86

(b)
Number of beads that Xylia had at first
= 1 u + 16 + 50 + 40
= 86 + 16 + 50 + 40
= 192 

Answer(s): (a) 86 ; (b) 192