Mary, Ivory and Elyse were playing with beads. Mary started with 40 beads and in the first game, she won
35 more beads from Ivory. In the second game, Mary lost
18 of her original number of beads to Elyse. Ivory lost as many beads as Mary to Elyse. In the final game, Mary won
14 of her original number of beads from Ivory. All of them ended up with the same number of beads.
- How many beads did Mary have in the end?
- How many beads did Ivory have at first?
|
Mary |
Ivory |
Elyse |
Before |
40 |
|
|
First game |
+ 24 |
- 24 |
|
Second game |
- 5 |
|
+ 5 |
|
|
- 5 |
+ 5 |
Final game |
+ 10 |
- 10 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Mary won from Ivory
=
35 x 40
= 24
Number of beads that Mary lost to Elyse
=
18 x 40
= 5
Number of beads that Mary won from Ivory
=
14 x 40
= 10
Number of beads that Mary had in the end
= 40 + 24 - 5 + 10
= 69
(b)
Number of beads that Ivory had at first
= 1 u + 10 + 5 + 24
= 69 + 10 + 5 + 24
= 108
Answer(s): (a) 69 ; (b) 108