Zoe, Jaslyn and Yoko were playing with beads. Zoe started with 80 beads and in the first game, she won
15 more beads from Jaslyn. In the second game, Zoe lost
18 of her original number of beads to Yoko. Jaslyn lost as many beads as Zoe to Yoko. In the final game, Zoe won
12 of her original number of beads from Jaslyn. All of them ended up with the same number of beads.
- How many beads did Zoe have in the end?
- How many beads did Jaslyn have at first?
|
Zoe |
Jaslyn |
Yoko |
Before |
80 |
|
|
First game |
+ 16 |
- 16 |
|
Second game |
- 10 |
|
+ 10 |
|
|
- 10 |
+ 10 |
Final game |
+ 40 |
- 40 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Zoe won from Jaslyn
=
15 x 80
= 16
Number of beads that Zoe lost to Yoko
=
18 x 80
= 10
Number of beads that Zoe won from Jaslyn
=
12 x 80
= 40
Number of beads that Zoe had in the end
= 80 + 16 - 10 + 40
= 126
(b)
Number of beads that Jaslyn had at first
= 1 u + 40 + 10 + 16
= 126 + 40 + 10 + 16
= 192
Answer(s): (a) 126 ; (b) 192