Esther, Raeann and Usha were playing with beads. Esther started with 28 beads and in the first game, she won
14 more beads from Raeann. In the second game, Esther lost
67 of her original number of beads to Usha. Raeann lost as many beads as Esther to Usha. In the final game, Esther won
12 of her original number of beads from Raeann. All of them ended up with the same number of beads.
- How many beads did Esther have in the end?
- How many beads did Raeann have at first?
|
Esther |
Raeann |
Usha |
Before |
28 |
|
|
First game |
+ 7 |
- 7 |
|
Second game |
- 24 |
|
+ 24 |
|
|
- 24 |
+ 24 |
Final game |
+ 14 |
- 14 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Esther won from Raeann
=
14 x 28
= 7
Number of beads that Esther lost to Usha
=
67 x 28
= 24
Number of beads that Esther won from Raeann
=
12 x 28
= 14
Number of beads that Esther had in the end
= 28 + 7 - 24 + 14
= 25
(b)
Number of beads that Raeann had at first
= 1 u + 14 + 24 + 7
= 25 + 14 + 24 + 7
= 70
Answer(s): (a) 25 ; (b) 70