Cathy, Cindy and Wendy were playing with beads. Cathy started with 84 beads and in the first game, she won
14 more beads from Cindy. In the second game, Cathy lost
27 of her original number of beads to Wendy. Cindy lost as many beads as Cathy to Wendy. In the final game, Cathy won
12 of her original number of beads from Cindy. All of them ended up with the same number of beads.
- How many beads did Cathy have in the end?
- How many beads did Cindy have at first?
|
Cathy |
Cindy |
Wendy |
Before |
84 |
|
|
First game |
+ 21 |
- 21 |
|
Second game |
- 24 |
|
+ 24 |
|
|
- 24 |
+ 24 |
Final game |
+ 42 |
- 42 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Cathy won from Cindy
=
14 x 84
= 21
Number of beads that Cathy lost to Wendy
=
27 x 84
= 24
Number of beads that Cathy won from Cindy
=
12 x 84
= 42
Number of beads that Cathy had in the end
= 84 + 21 - 24 + 42
= 123
(b)
Number of beads that Cindy had at first
= 1 u + 42 + 24 + 21
= 123 + 42 + 24 + 21
= 210
Answer(s): (a) 123 ; (b) 210