Sarah, Jean and Kylie were playing with beads. Sarah started with 56 beads and in the first game, she won ³₄ more beads from Jean. In the second game, Sarah lost ⁴₇ of her original number of beads to Kylie. Jean lost as many beads as Sarah to Kylie. In the final game, Sarah won ¹₂ of her original number of beads from Jean. All of them ended up with the same number of beads.

1. How many beads did Sarah have in the end?
2. How many beads did Jean have at first?

	Sarah	Jean	Kylie
Before	56
First game	+ 42	- 42
Second game	- 32		+ 32
		- 32	+ 32
Final game	+ 28	- 28
After	1 u	1 u	1 u

(a)
Number of beads that Sarah won from Jean
= ³₄ x 56
= 42

Number of beads that Sarah lost to Kylie
= ⁴₇ x 56
= 32

Number of beads that Sarah won from Jean
= ¹₂ x 56
= 28

Number of beads that Sarah had in the end
= 56 + 42 - 32 + 28
= 94

(b)
Number of beads that Jean had at first
= 1 u + 28 + 32 + 42
= 94 + 28 + 32 + 42
= 196 

Answer(s): (a) 94 ; (b) 196