Nicole, Dana and Lucy were playing with beads. Nicole started with 40 beads and in the first game, she won
15 more beads from Dana. In the second game, Nicole lost
38 of her original number of beads to Lucy. Dana lost as many beads as Nicole to Lucy. In the final game, Nicole won
12 of her original number of beads from Dana. All of them ended up with the same number of beads.
- How many beads did Nicole have in the end?
- How many beads did Dana have at first?
|
Nicole |
Dana |
Lucy |
Before |
40 |
|
|
First game |
+ 8 |
- 8 |
|
Second game |
- 15 |
|
+ 15 |
|
|
- 15 |
+ 15 |
Final game |
+ 20 |
- 20 |
|
After |
1 u |
1 u |
1 u |
(a)
Number of beads that Nicole won from Dana
=
15 x 40
= 8
Number of beads that Nicole lost to Lucy
=
38 x 40
= 15
Number of beads that Nicole won from Dana
=
12 x 40
= 20
Number of beads that Nicole had in the end
= 40 + 8 - 15 + 20
= 53
(b)
Number of beads that Dana had at first
= 1 u + 20 + 15 + 8
= 53 + 20 + 15 + 8
= 96
Answer(s): (a) 53 ; (b) 96