Marion, Vanessa and Xylia were playing with beads. Marion started with 56 beads and in the first game, she won ¹₂ more beads from Vanessa. In the second game, Marion lost ⁶₇ of her original number of beads to Xylia. Vanessa lost as many beads as Marion to Xylia. In the final game, Marion won ¹₄ of her original number of beads from Vanessa. All of them ended up with the same number of beads.

1. How many beads did Marion have in the end?
2. How many beads did Vanessa have at first?

	Marion	Vanessa	Xylia
Before	56
First game	+ 28	- 28
Second game	- 48		+ 48
		- 48	+ 48
Final game	+ 14	- 14
After	1 u	1 u	1 u

(a)
Number of beads that Marion won from Vanessa
= ¹₂ x 56
= 28

Number of beads that Marion lost to Xylia
= ⁶₇ x 56
= 48

Number of beads that Marion won from Vanessa
= ¹₄ x 56
= 14

Number of beads that Marion had in the end
= 56 + 28 - 48 + 14
= 50

(b)
Number of beads that Vanessa had at first
= 1 u + 14 + 48 + 28
= 50 + 14 + 48 + 28
= 140 

Answer(s): (a) 50 ; (b) 140