Oliver, Ryan and Seth shared $473. During a shopping trip, Oliver spent
38 of his share, Ryan spent
25 of his share and Seth spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Oliver and Ryan have than Seth at first?
| |
Oliver |
Ryan |
Seth |
Total |
| Before |
8x2 =
16 u |
5x3 =
15 u |
2x6 =
12 u |
$473 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
3x3 =
9 u |
1x6 =
6 u |
|
The amounts that Oliver, Ryan and Seth spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 15 u + 12 u
= 43 u
43 u = 473
1 u = 473 ÷ 43 = 11
Amount that Oliver and Ryan have at first
= 16 u + 15 u
= 31 u
Amount that Oliver and Ryan have more than Seth at first
= 31 u - 12 u
= 19 u
= 19 x 11
= $209
Answer(s): $209
