Ahmad, Tommy and Julian shared $564. During a shopping trip, Ahmad spent ³₇ of his share, Tommy spent ²₅ of his share and Julian spent ¹₃ of his share. Given that all three boys each spent the same amount of money, how much more money do Ahmad and Tommy have than Julian at first?

	Ahmad	Tommy	Julian	Total
Before	7x2 = 14 u	5x3 = 15 u	3x6 = 18 u	$564
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	4x2 = 8 u	3x3 = 9 u	2x6 = 12 u

The amounts that Ahmad, Tommy and Julian spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 14 u + 15 u + 18 u
= 47 u

47 u = 564

1 u = 564 ÷ 47 = 12

Amount that Ahmad and Tommy have at first
= 14 u + 15 u
= 29 u

Amount that Ahmad and Tommy have more than Julian at first
= 29 u - 18 u
= 11 u
= 11 x 12
= $132

Answer(s): $132