Reggie, Japheth and Dylan shared $246. During a shopping trip, Reggie spent ²₇ of his share, Japheth spent ³₄ of his share and Dylan spent ¹₂ of his share. Given that all three boys each spent the same amount of money, how much more money do Reggie and Japheth have than Dylan at first?

	Reggie	Japheth	Dylan	Total
Before	7x3 = 21 u	4x2 = 8 u	2x6 = 12 u	$246
Change	- 2x3 = - 6 u	- 3x2 = - 6 u	- 1x6 = - 6 u
After	5x3 = 15 u	1x2 = 2 u	1x6 = 6 u

The amounts that Reggie, Japheth and Dylan spent is the same.  Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.

Amounts that the 3 boys had at first
= 21 u + 8 u + 12 u
= 41 u

41 u = 246

1 u = 246 ÷ 41 = 6

Amount that Reggie and Japheth have at first
= 21 u + 8 u
= 29 u

Amount that Reggie and Japheth have more than Dylan at first
= 29 u - 12 u
= 17 u
= 17 x 6
= $102

Answer(s): $102