Cole, Flynn and Brandon shared $424. During a shopping trip, Cole spent
37 of his share, Flynn spent
25 of his share and Brandon spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Cole and Flynn have than Brandon at first?
| |
Cole |
Flynn |
Brandon |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
4x6 =
24 u |
$424 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Cole, Flynn and Brandon spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u
53 u = 424
1 u = 424 ÷ 53 = 8
Amount that Cole and Flynn have at first
= 14 u + 15 u
= 29 u
Amount that Cole and Flynn have more than Brandon at first
= 29 u - 24 u
= 5 u
= 5 x 8
= $40
Answer(s): $40
