Caden, Bryan and Julian shared $183. During a shopping trip, Caden spent ³₈ of his share, Bryan spent ²₇ of his share and Julian spent ¹₄ of his share. Given that all three boys each spent the same amount of money, how much more money do Caden and Bryan have than Julian in the end?

	Caden	Bryan	Julian	Total
Before	8x2 = 16 u	7x3 = 21 u	4x6 = 24 u	$183
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	5x2 = 10 u	5x3 = 15 u	3x6 = 18 u

The amounts that Caden, Bryan and Julian spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 16 u + 21 u + 24 u
= 61 u

61 u = 183

1 u = 183 ÷ 61 = 3

Amount that Caden and Bryan have in the end
= 10 u + 15 u
= 25 u

Amount that Caden and Bryan have more than Julian in the end
= 25 u - 18 u
= 7 u
= 7 x 3
= $21

Answer(s): $21