Reggie, Archie and Caden shared $244. During a shopping trip, Reggie spent
38 of his share, Archie spent
27 of his share and Caden spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Reggie and Archie have than Caden in the end?
|
Reggie |
Archie |
Caden |
Total |
Before |
8x2 = 16 u |
7x3 = 21 u |
4x6 = 24 u |
$244 |
Change |
- 3x2 = - 6 u |
- 2x3 = - 6 u |
- 1x6 = - 6 u |
|
After |
5x2 = 10 u |
5x3 = 15 u |
3x6 = 18 u |
|
The amounts that Reggie, Archie and Caden spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 21 u + 24 u
= 61 u
61 u = 244
1 u = 244 ÷ 61 = 4
Amount that Reggie and Archie have in the end
= 10 u + 15 u
= 25 u
Amount that Reggie and Archie have more than Caden in the end
= 25 u - 18 u
= 7 u
= 7 x 4
= $28
Answer(s): $28