Dylan, Wesley and Harry shared $122. During a shopping trip, Dylan spent ³₈ of his share, Wesley spent ²₇ of his share and Harry spent ¹₄ of his share. Given that all three boys each spent the same amount of money, how much more money do Dylan and Wesley have than Harry in the end?

	Dylan	Wesley	Harry	Total
Before	8x2 = 16 u	7x3 = 21 u	4x6 = 24 u	$122
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	5x2 = 10 u	5x3 = 15 u	3x6 = 18 u

The amounts that Dylan, Wesley and Harry spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 16 u + 21 u + 24 u
= 61 u

61 u = 122

1 u = 122 ÷ 61 = 2

Amount that Dylan and Wesley have in the end
= 10 u + 15 u
= 25 u

Amount that Dylan and Wesley have more than Harry in the end
= 25 u - 18 u
= 7 u
= 7 x 2
= $14

Answer(s): $14