Henry, Neave and Riordan shared $583. During a shopping trip, Henry spent ³₇ of his share, Neave spent ²₅ of his share and Riordan spent ¹₄ of his share. Given that all three boys each spent the same amount of money, how much more money do Henry and Neave have than Riordan in the end?

	Henry	Neave	Riordan	Total
Before	7x2 = 14 u	5x3 = 15 u	4x6 = 24 u	$583
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	4x2 = 8 u	3x3 = 9 u	3x6 = 18 u

The amounts that Henry, Neave and Riordan spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u

53 u = 583

1 u = 583 ÷ 53 = 11

Amount that Henry and Neave have in the end
= 8 u + 9 u
= 17 u

Amount that Henry and Neave have more than Riordan in the end
= 17 u - 18 u
= -1 u
= -1 x 11
= $-11

Answer(s): $-11