Vaidev, Oliver and Mark shared $376. During a shopping trip, Vaidev spent
27 of his share, Oliver spent
34 of his share and Mark spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Vaidev and Oliver have than Mark at first?
| |
Vaidev |
Oliver |
Mark |
Total |
| Before |
7x3 =
21 u |
4x2 =
8 u |
3x6 =
18 u |
$376 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
1x2 =
2 u |
2x6 =
12 u |
|
The amounts that Vaidev, Oliver and Mark spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 8 u + 18 u
= 47 u
47 u = 376
1 u = 376 ÷ 47 = 8
Amount that Vaidev and Oliver have at first
= 21 u + 8 u
= 29 u
Amount that Vaidev and Oliver have more than Mark at first
= 29 u - 18 u
= 11 u
= 11 x 8
= $88
Answer(s): $88
