Ryan, Ahmad and Flynn shared $330. During a shopping trip, Ryan spent
27 of his share, Ahmad spent
35 of his share and Flynn spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Ryan and Ahmad have than Flynn at first?
| |
Ryan |
Ahmad |
Flynn |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
4x6 =
24 u |
$330 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
3x6 =
18 u |
|
The amounts that Ryan, Ahmad and Flynn spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 24 u
= 55 u
55 u = 330
1 u = 330 ÷ 55 = 6
Amount that Ryan and Ahmad have at first
= 21 u + 10 u
= 31 u
Amount that Ryan and Ahmad have more than Flynn at first
= 31 u - 24 u
= 7 u
= 7 x 6
= $42
Answer(s): $42
