Tim, Ethan and Neave shared $470. During a shopping trip, Tim spent
27 of his share, Ethan spent
34 of his share and Neave spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Tim and Ethan have than Neave in the end?
| |
Tim |
Ethan |
Neave |
Total |
| Before |
7x3 =
21 u |
4x2 =
8 u |
3x6 =
18 u |
$470 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
1x2 =
2 u |
2x6 =
12 u |
|
The amounts that Tim, Ethan and Neave spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 8 u + 18 u
= 47 u
47 u = 470
1 u = 470 ÷ 47 = 10
Amount that Tim and Ethan have in the end
= 15 u + 2 u
= 17 u
Amount that Tim and Ethan have more than Neave in the end
= 17 u - 12 u
= 5 u
= 5 x 10
= $50
Answer(s): $50
