Zeph, Howard and Will shared $220. During a shopping trip, Zeph spent
38 of his share, Howard spent
25 of his share and Will spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Zeph and Howard have than Will at first?
| |
Zeph |
Howard |
Will |
Total |
| Before |
8x2 =
16 u |
5x3 =
15 u |
4x6 =
24 u |
$220 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Zeph, Howard and Will spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 15 u + 24 u
= 55 u
55 u = 220
1 u = 220 ÷ 55 = 4
Amount that Zeph and Howard have at first
= 16 u + 15 u
= 31 u
Amount that Zeph and Howard have more than Will at first
= 31 u - 24 u
= 7 u
= 7 x 4
= $28
Answer(s): $28
