Caden, Sam and Harry shared $539. During a shopping trip, Caden spent
27 of his share, Sam spent
35 of his share and Harry spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Caden and Sam have than Harry in the end?
| |
Caden |
Sam |
Harry |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
3x6 =
18 u |
$539 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
2x6 =
12 u |
|
The amounts that Caden, Sam and Harry spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 18 u
= 49 u
49 u = 539
1 u = 539 ÷ 49 = 11
Amount that Caden and Sam have in the end
= 15 u + 4 u
= 19 u
Amount that Caden and Sam have more than Harry in the end
= 19 u - 12 u
= 7 u
= 7 x 11
= $77
Answer(s): $77
