Bryan, Ivan and Seth shared $155. During a shopping trip, Bryan spent
35 of his share, Ivan spent
23 of his share and Seth spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Bryan and Ivan have than Seth in the end?
| |
Bryan |
Ivan |
Seth |
Total |
| Before |
5x2 =
10 u |
3x3 =
9 u |
2x6 =
12 u |
$155 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
2x2 =
4 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Bryan, Ivan and Seth spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 10 u + 9 u + 12 u
= 31 u
31 u = 155
1 u = 155 ÷ 31 = 5
Amount that Bryan and Ivan have in the end
= 4 u + 3 u
= 7 u
Amount that Bryan and Ivan have more than Seth in the end
= 7 u - 6 u
= 1 u
= 1 x 5
= $5
Answer(s): $5
