Tom, Fabian and Luis shared $488. During a shopping trip, Tom spent
38 of his share, Fabian spent
27 of his share and Luis spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Tom and Fabian have than Luis at first?
| |
Tom |
Fabian |
Luis |
Total |
| Before |
8x2 =
16 u |
7x3 =
21 u |
4x6 =
24 u |
$488 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
5x3 =
15 u |
3x6 =
18 u |
|
The amounts that Tom, Fabian and Luis spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 21 u + 24 u
= 61 u
61 u = 488
1 u = 488 ÷ 61 = 8
Amount that Tom and Fabian have at first
= 16 u + 21 u
= 37 u
Amount that Tom and Fabian have more than Luis at first
= 37 u - 24 u
= 13 u
= 13 x 8
= $104
Answer(s): $104
