Julian, Ryan and Jenson shared $205. During a shopping trip, Julian spent
27 of his share, Ryan spent
34 of his share and Jenson spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Julian and Ryan have than Jenson at first?
| |
Julian |
Ryan |
Jenson |
Total |
| Before |
7x3 =
21 u |
4x2 =
8 u |
2x6 =
12 u |
$205 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
1x2 =
2 u |
1x6 =
6 u |
|
The amounts that Julian, Ryan and Jenson spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 8 u + 12 u
= 41 u
41 u = 205
1 u = 205 ÷ 41 = 5
Amount that Julian and Ryan have at first
= 21 u + 8 u
= 29 u
Amount that Julian and Ryan have more than Jenson at first
= 29 u - 12 u
= 17 u
= 17 x 5
= $85
Answer(s): $85
