Reggie, Pierre and Neave shared $282. During a shopping trip, Reggie spent ²₇ of his share, Pierre spent ³₄ of his share and Neave spent ¹₃ of his share. Given that all three boys each spent the same amount of money, how much more money do Reggie and Pierre have than Neave at first?

	Reggie	Pierre	Neave	Total
Before	7x3 = 21 u	4x2 = 8 u	3x6 = 18 u	$282
Change	- 2x3 = - 6 u	- 3x2 = - 6 u	- 1x6 = - 6 u
After	5x3 = 15 u	1x2 = 2 u	2x6 = 12 u

The amounts that Reggie, Pierre and Neave spent is the same.  Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.

Amounts that the 3 boys had at first
= 21 u + 8 u + 18 u
= 47 u

47 u = 282

1 u = 282 ÷ 47 = 6

Amount that Reggie and Pierre have at first
= 21 u + 8 u
= 29 u

Amount that Reggie and Pierre have more than Neave at first
= 29 u - 18 u
= 11 u
= 11 x 6
= $66

Answer(s): $66