Glen, Ahmad and Jeremy shared $301. During a shopping trip, Glen spent
38 of his share, Ahmad spent
25 of his share and Jeremy spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Glen and Ahmad have than Jeremy at first?
| |
Glen |
Ahmad |
Jeremy |
Total |
| Before |
8x2 =
16 u |
5x3 =
15 u |
2x6 =
12 u |
$301 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
3x3 =
9 u |
1x6 =
6 u |
|
The amounts that Glen, Ahmad and Jeremy spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 15 u + 12 u
= 43 u
43 u = 301
1 u = 301 ÷ 43 = 7
Amount that Glen and Ahmad have at first
= 16 u + 15 u
= 31 u
Amount that Glen and Ahmad have more than Jeremy at first
= 31 u - 12 u
= 19 u
= 19 x 7
= $133
Answer(s): $133
