Simon, Luis and Perry shared $210. During a shopping trip, Simon spent
25 of his share, Luis spent
34 of his share and Perry spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Simon and Luis have than Perry at first?
| |
Simon |
Luis |
Perry |
Total |
| Before |
5x3 =
15 u |
4x2 =
8 u |
2x6 =
12 u |
$210 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
3x3 =
9 u |
1x2 =
2 u |
1x6 =
6 u |
|
The amounts that Simon, Luis and Perry spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 15 u + 8 u + 12 u
= 35 u
35 u = 210
1 u = 210 ÷ 35 = 6
Amount that Simon and Luis have at first
= 15 u + 8 u
= 23 u
Amount that Simon and Luis have more than Perry at first
= 23 u - 12 u
= 11 u
= 11 x 6
= $66
Answer(s): $66
