Henry, Tom and Oscar shared $195. During a shopping trip, Henry spent
29 of his share, Tom spent
37 of his share and Oscar spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Henry and Tom have than Oscar in the end?
| |
Henry |
Tom |
Oscar |
Total |
| Before |
9x3 =
27 u |
7x2 =
14 u |
4x6 =
24 u |
$195 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
7x3 =
21 u |
4x2 =
8 u |
3x6 =
18 u |
|
The amounts that Henry, Tom and Oscar spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 27 u + 14 u + 24 u
= 65 u
65 u = 195
1 u = 195 ÷ 65 = 3
Amount that Henry and Tom have in the end
= 21 u + 8 u
= 29 u
Amount that Henry and Tom have more than Oscar in the end
= 29 u - 18 u
= 11 u
= 11 x 3
= $33
Answer(s): $33
