Cole, Liam and Carl shared $70. During a shopping trip, Cole spent
25 of his share, Liam spent
34 of his share and Carl spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Cole and Liam have than Carl in the end?
| |
Cole |
Liam |
Carl |
Total |
| Before |
5x3 =
15 u |
4x2 =
8 u |
2x6 =
12 u |
$70 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
3x3 =
9 u |
1x2 =
2 u |
1x6 =
6 u |
|
The amounts that Cole, Liam and Carl spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 15 u + 8 u + 12 u
= 35 u
35 u = 70
1 u = 70 ÷ 35 = 2
Amount that Cole and Liam have in the end
= 9 u + 2 u
= 11 u
Amount that Cole and Liam have more than Carl in the end
= 11 u - 6 u
= 5 u
= 5 x 2
= $10
Answer(s): $10
