Owen, Ivan and Rael shared $310. During a shopping trip, Owen spent
35 of his share, Ivan spent
23 of his share and Rael spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Owen and Ivan have than Rael at first?
| |
Owen |
Ivan |
Rael |
Total |
| Before |
5x2 =
10 u |
3x3 =
9 u |
2x6 =
12 u |
$310 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
2x2 =
4 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Owen, Ivan and Rael spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 10 u + 9 u + 12 u
= 31 u
31 u = 310
1 u = 310 ÷ 31 = 10
Amount that Owen and Ivan have at first
= 10 u + 9 u
= 19 u
Amount that Owen and Ivan have more than Rael at first
= 19 u - 12 u
= 7 u
= 7 x 10
= $70
Answer(s): $70
