Perry, Ivan and Tommy shared $470. During a shopping trip, Perry spent
37 of his share, Ivan spent
25 of his share and Tommy spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Perry and Ivan have than Tommy in the end?
| |
Perry |
Ivan |
Tommy |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
3x6 =
18 u |
$470 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
2x6 =
12 u |
|
The amounts that Perry, Ivan and Tommy spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 18 u
= 47 u
47 u = 470
1 u = 470 ÷ 47 = 10
Amount that Perry and Ivan have in the end
= 8 u + 9 u
= 17 u
Amount that Perry and Ivan have more than Tommy in the end
= 17 u - 12 u
= 5 u
= 5 x 10
= $50
Answer(s): $50
