Caden, Perry and Billy shared $671. During a shopping trip, Caden spent
38 of his share, Perry spent
27 of his share and Billy spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Caden and Perry have than Billy at first?
| |
Caden |
Perry |
Billy |
Total |
| Before |
8x2 =
16 u |
7x3 =
21 u |
4x6 =
24 u |
$671 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
5x3 =
15 u |
3x6 =
18 u |
|
The amounts that Caden, Perry and Billy spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 21 u + 24 u
= 61 u
61 u = 671
1 u = 671 ÷ 61 = 11
Amount that Caden and Perry have at first
= 16 u + 21 u
= 37 u
Amount that Caden and Perry have more than Billy at first
= 37 u - 24 u
= 13 u
= 13 x 11
= $143
Answer(s): $143
