Tommy, John and Neave shared $106. During a shopping trip, Tommy spent
37 of his share, John spent
25 of his share and Neave spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Tommy and John have than Neave in the end?
| |
Tommy |
John |
Neave |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
4x6 =
24 u |
$106 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Tommy, John and Neave spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u
53 u = 106
1 u = 106 ÷ 53 = 2
Amount that Tommy and John have in the end
= 8 u + 9 u
= 17 u
Amount that Tommy and John have more than Neave in the end
= 17 u - 18 u
= -1 u
= -1 x 2
= $-2
Answer(s): $-2
