John, Justin and Owen shared $70. During a shopping trip, John spent
25 of his share, Justin spent
34 of his share and Owen spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do John and Justin have than Owen at first?
| |
John |
Justin |
Owen |
Total |
| Before |
5x3 =
15 u |
4x2 =
8 u |
2x6 =
12 u |
$70 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
3x3 =
9 u |
1x2 =
2 u |
1x6 =
6 u |
|
The amounts that John, Justin and Owen spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 15 u + 8 u + 12 u
= 35 u
35 u = 70
1 u = 70 ÷ 35 = 2
Amount that John and Justin have at first
= 15 u + 8 u
= 23 u
Amount that John and Justin have more than Owen at first
= 23 u - 12 u
= 11 u
= 11 x 2
= $22
Answer(s): $22
