Tom, Neave and Oliver shared $588. During a shopping trip, Tom spent
27 of his share, Neave spent
35 of his share and Oliver spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Tom and Neave have than Oliver in the end?
| |
Tom |
Neave |
Oliver |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
3x6 =
18 u |
$588 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
2x6 =
12 u |
|
The amounts that Tom, Neave and Oliver spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 18 u
= 49 u
49 u = 588
1 u = 588 ÷ 49 = 12
Amount that Tom and Neave have in the end
= 15 u + 4 u
= 19 u
Amount that Tom and Neave have more than Oliver in the end
= 19 u - 12 u
= 7 u
= 7 x 12
= $84
Answer(s): $84
