Jeremy, Vincent and Zeph shared $473. During a shopping trip, Jeremy spent ³₈ of his share, Vincent spent ²₅ of his share and Zeph spent ¹₂ of his share. Given that all three boys each spent the same amount of money, how much more money do Jeremy and Vincent have than Zeph at first?

	Jeremy	Vincent	Zeph	Total
Before	8x2 = 16 u	5x3 = 15 u	2x6 = 12 u	$473
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	5x2 = 10 u	3x3 = 9 u	1x6 = 6 u

The amounts that Jeremy, Vincent and Zeph spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 16 u + 15 u + 12 u
= 43 u

43 u = 473

1 u = 473 ÷ 43 = 11

Amount that Jeremy and Vincent have at first
= 16 u + 15 u
= 31 u

Amount that Jeremy and Vincent have more than Zeph at first
= 31 u - 12 u
= 19 u
= 19 x 11
= $209

Answer(s): $209