Vincent, Neave and Cody shared $246. During a shopping trip, Vincent spent
27 of his share, Neave spent
34 of his share and Cody spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Vincent and Neave have than Cody in the end?
|
Vincent |
Neave |
Cody |
Total |
Before |
7x3 = 21 u |
4x2 = 8 u |
2x6 = 12 u |
$246 |
Change |
- 2x3 = - 6 u |
- 3x2 = - 6 u |
- 1x6 = - 6 u |
|
After |
5x3 = 15 u |
1x2 = 2 u |
1x6 = 6 u |
|
The amounts that Vincent, Neave and Cody spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 8 u + 12 u
= 41 u
41 u = 246
1 u = 246 ÷ 41 = 6
Amount that Vincent and Neave have in the end
= 15 u + 2 u
= 17 u
Amount that Vincent and Neave have more than Cody in the end
= 17 u - 6 u
= 11 u
= 11 x 6
= $66
Answer(s): $66