Carl, Julian and Jenson shared $122. During a shopping trip, Carl spent
38 of his share, Julian spent
27 of his share and Jenson spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Carl and Julian have than Jenson at first?
| |
Carl |
Julian |
Jenson |
Total |
| Before |
8x2 =
16 u |
7x3 =
21 u |
4x6 =
24 u |
$122 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
5x3 =
15 u |
3x6 =
18 u |
|
The amounts that Carl, Julian and Jenson spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 21 u + 24 u
= 61 u
61 u = 122
1 u = 122 ÷ 61 = 2
Amount that Carl and Julian have at first
= 16 u + 21 u
= 37 u
Amount that Carl and Julian have more than Jenson at first
= 37 u - 24 u
= 13 u
= 13 x 2
= $26
Answer(s): $26
