Rael, Pierre and Harry shared $318. During a shopping trip, Rael spent
37 of his share, Pierre spent
25 of his share and Harry spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Rael and Pierre have than Harry in the end?
| |
Rael |
Pierre |
Harry |
Total |
| Before |
7x2 =
14 u |
5x3 =
15 u |
4x6 =
24 u |
$318 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
4x2 =
8 u |
3x3 =
9 u |
3x6 =
18 u |
|
The amounts that Rael, Pierre and Harry spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 14 u + 15 u + 24 u
= 53 u
53 u = 318
1 u = 318 ÷ 53 = 6
Amount that Rael and Pierre have in the end
= 8 u + 9 u
= 17 u
Amount that Rael and Pierre have more than Harry in the end
= 17 u - 18 u
= -1 u
= -1 x 6
= $-6
Answer(s): $-6
