Wesley, Luis and Glen shared $588. During a shopping trip, Wesley spent
27 of his share, Luis spent
35 of his share and Glen spent
13 of his share. Given that all three boys each spent the same amount of money, how much more money do Wesley and Luis have than Glen at first?
| |
Wesley |
Luis |
Glen |
Total |
| Before |
7x3 =
21 u |
5x2 =
10 u |
3x6 =
18 u |
$588 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x3 =
15 u |
2x2 =
4 u |
2x6 =
12 u |
|
The amounts that Wesley, Luis and Glen spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 21 u + 10 u + 18 u
= 49 u
49 u = 588
1 u = 588 ÷ 49 = 12
Amount that Wesley and Luis have at first
= 21 u + 10 u
= 31 u
Amount that Wesley and Luis have more than Glen at first
= 31 u - 18 u
= 13 u
= 13 x 12
= $156
Answer(s): $156
