Fred, Tim and Ryan shared $549. During a shopping trip, Fred spent
38 of his share, Tim spent
27 of his share and Ryan spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Fred and Tim have than Ryan in the end?
| |
Fred |
Tim |
Ryan |
Total |
| Before |
8x2 =
16 u |
7x3 =
21 u |
4x6 =
24 u |
$549 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
5x2 =
10 u |
5x3 =
15 u |
3x6 =
18 u |
|
The amounts that Fred, Tim and Ryan spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 16 u + 21 u + 24 u
= 61 u
61 u = 549
1 u = 549 ÷ 61 = 9
Amount that Fred and Tim have in the end
= 10 u + 15 u
= 25 u
Amount that Fred and Tim have more than Ryan in the end
= 25 u - 18 u
= 7 u
= 7 x 9
= $63
Answer(s): $63
