Oliver, Pierre and Warren shared $343. During a shopping trip, Oliver spent ²₇ of his share, Pierre spent ³₅ of his share and Warren spent ¹₃ of his share. Given that all three boys each spent the same amount of money, how much more money do Oliver and Pierre have than Warren at first?

	Oliver	Pierre	Warren	Total
Before	7x3 = 21 u	5x2 = 10 u	3x6 = 18 u	$343
Change	- 2x3 = - 6 u	- 3x2 = - 6 u	- 1x6 = - 6 u
After	5x3 = 15 u	2x2 = 4 u	2x6 = 12 u

The amounts that Oliver, Pierre and Warren spent is the same.  Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.

Amounts that the 3 boys had at first
= 21 u + 10 u + 18 u
= 49 u

49 u = 343

1 u = 343 ÷ 49 = 7

Amount that Oliver and Pierre have at first
= 21 u + 10 u
= 31 u

Amount that Oliver and Pierre have more than Warren at first
= 31 u - 18 u
= 13 u
= 13 x 7
= $91

Answer(s): $91