Elijah, Tom and Pierre shared $325. During a shopping trip, Elijah spent
29 of his share, Tom spent
37 of his share and Pierre spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Elijah and Tom have than Pierre at first?
| |
Elijah |
Tom |
Pierre |
Total |
| Before |
9x3 =
27 u |
7x2 =
14 u |
4x6 =
24 u |
$325 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
7x3 =
21 u |
4x2 =
8 u |
3x6 =
18 u |
|
The amounts that Elijah, Tom and Pierre spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 27 u + 14 u + 24 u
= 65 u
65 u = 325
1 u = 325 ÷ 65 = 5
Amount that Elijah and Tom have at first
= 27 u + 14 u
= 41 u
Amount that Elijah and Tom have more than Pierre at first
= 41 u - 24 u
= 17 u
= 17 x 5
= $85
Answer(s): $85
