Gabriel, Ryan and Xavier shared $205. During a shopping trip, Gabriel spent ²₅ of his share, Ryan spent ³₄ of his share and Xavier spent ¹₃ of his share. Given that all three boys each spent the same amount of money, how much more money do Gabriel and Ryan have than Xavier in the end?

	Gabriel	Ryan	Xavier	Total
Before	5x3 = 15 u	4x2 = 8 u	3x6 = 18 u	$205
Change	- 2x3 = - 6 u	- 3x2 = - 6 u	- 1x6 = - 6 u
After	3x3 = 9 u	1x2 = 2 u	2x6 = 12 u

The amounts that Gabriel, Ryan and Xavier spent is the same.  Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.

Amounts that the 3 boys had at first
= 15 u + 8 u + 18 u
= 41 u

41 u = 205

1 u = 205 ÷ 41 = 5

Amount that Gabriel and Ryan have in the end
= 9 u + 2 u
= 11 u

Amount that Gabriel and Ryan have more than Xavier in the end
= 11 u - 12 u
= -1 u
= -1 x 5
= $-5

Answer(s): $-5