Harry, Reggie and Ethan shared $87. During a shopping trip, Harry spent
34 of his share, Reggie spent
23 of his share and Ethan spent
12 of his share. Given that all three boys each spent the same amount of money, how much more money do Harry and Reggie have than Ethan at first?
| |
Harry |
Reggie |
Ethan |
Total |
| Before |
4x2 =
8 u |
3x3 =
9 u |
2x6 =
12 u |
$87 |
| Change |
- 3x2 =
- 6 u |
- 2x3 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
1x2 =
2 u |
1x3 =
3 u |
1x6 =
6 u |
|
The amounts that Harry, Reggie and Ethan spent is the same. Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.
Amounts that the 3 boys had at first
= 8 u + 9 u + 12 u
= 29 u
29 u = 87
1 u = 87 ÷ 29 = 3
Amount that Harry and Reggie have at first
= 8 u + 9 u
= 17 u
Amount that Harry and Reggie have more than Ethan at first
= 17 u - 12 u
= 5 u
= 5 x 3
= $15
Answer(s): $15
