Lee, Wesley and Perry shared $715. During a shopping trip, Lee spent
29 of his share, Wesley spent
37 of his share and Perry spent
14 of his share. Given that all three boys each spent the same amount of money, how much more money do Lee and Wesley have than Perry at first?
| |
Lee |
Wesley |
Perry |
Total |
| Before |
9x3 =
27 u |
7x2 =
14 u |
4x6 =
24 u |
$715 |
| Change |
- 2x3 =
- 6 u |
- 3x2 =
- 6 u |
- 1x6 =
- 6 u |
|
| After |
7x3 =
21 u |
4x2 =
8 u |
3x6 =
18 u |
|
The amounts that Lee, Wesley and Perry spent is the same. Make the amounts that each boy spent the same. LCM of 2, 3 and 1 is 6.
Amounts that the 3 boys had at first
= 27 u + 14 u + 24 u
= 65 u
65 u = 715
1 u = 715 ÷ 65 = 11
Amount that Lee and Wesley have at first
= 27 u + 14 u
= 41 u
Amount that Lee and Wesley have more than Perry at first
= 41 u - 24 u
= 17 u
= 17 x 11
= $187
Answer(s): $187
