Neave, Charlie and Ivan shared $430. During a shopping trip, Neave spent ³₈ of his share, Charlie spent ²₅ of his share and Ivan spent ¹₂ of his share. Given that all three boys each spent the same amount of money, how much more money do Neave and Charlie have than Ivan in the end?

	Neave	Charlie	Ivan	Total
Before	8x2 = 16 u	5x3 = 15 u	2x6 = 12 u	$430
Change	- 3x2 = - 6 u	- 2x3 = - 6 u	- 1x6 = - 6 u
After	5x2 = 10 u	3x3 = 9 u	1x6 = 6 u

The amounts that Neave, Charlie and Ivan spent is the same.  Make the amounts that each boy spent the same. LCM of 3, 2 and 1 is 6.

Amounts that the 3 boys had at first
= 16 u + 15 u + 12 u
= 43 u

43 u = 430

1 u = 430 ÷ 43 = 10

Amount that Neave and Charlie have in the end
= 10 u + 9 u
= 19 u

Amount that Neave and Charlie have more than Ivan in the end
= 19 u - 6 u
= 13 u
= 13 x 10
= $130

Answer(s): $130